2x^2-125=1625

Solution for 2x^2-125=1625 equation:

2x^2-125=1625

We move all terms to the left:

2x^2-125-(1625)=0

We add all the numbers together, and all the variables

2x^2-1750=0

a = 2; b = 0; c = -1750;
Δ = b2-4ac
Δ = 02-4·2·(-1750)
Δ = 14000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14000}=\sqrt{400*35}=\sqrt{400}*\sqrt{35}=20\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{35}}{2*2}=\frac{0-20\sqrt{35}}{4}
=-\frac{20\sqrt{35}}{4}
=-5\sqrt{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{35}}{2*2}=\frac{0+20\sqrt{35}}{4}
=\frac{20\sqrt{35}}{4}
=5\sqrt{35}
$